1) In the baseball diamond, we have a man running from second to
third. In order to rearrange this scenario into familiar terms, I will lean
the diamond a bit to rest it on its lower left side, making the line the
player is running on the yaxis, and the "third to home" line
is the xaxis. Step 1  The variables: y = 60 y' = 28 (It is decreasing by 28 every second, as he runs DOWNWARD) x = 80 (This is a constant; when you differentiate, it will go to zero) z = ?? (z is now the distance from him to the plate) z' = ?? Step 2  The equation relating our variables is x^{2} + y^{2} = z^{2} Now solve for z using this last equation with x = 80 and y = 60. I get z = 100. Step 3  Differentiate x^{2} + y^{2} = z^{2}. 0 + 2yy' = 2zz' (x is a CONSTANT, stop bothering me about that everybody. The distance from third to home remains at 80 feet throughout the entire baseball game) yy' = zz' (I divide both sides by 2) Note that z', or the changing distance, is what we have been asked to solve. Step 4  Fill in the variables you know: (60)(28) = (100)(z') Solve for z'. I'm not going to do everything for you. Incidentally, you will get a negative number for z. The reason is because when the player is running downward, y is decreasing, and therefore z is decreasing. The change in z is then going to be negative. However, when I phrased my question, I didn't ask how fast z is changing, I asked how fast it is decreasing, and it is decreasing at a positive rate. For example, if I run forward at 10 feet per second, then I run backward at 10 fps. 2) Step 1 
